Form 10: Special Cases in Substitution - No Solution Exercise

Form 10: Special Cases in Substitution - No Solution

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Form 10: Special Cases in Substitution - No Solution

Identify special cases in the substitution method where a system of linear equations has no solution.

Questions

  1. MultiChoice

    Solve by substitution: y = 2x + 3 and 2x - y = 4.

  2. MultiChoice

    What resulting equation indicates that a system has no solution during substitution?

  3. MultiChoice

    Solve by substitution: y = 3x + 1 and y = 3x + 4.

  4. MultiChoice

    Solve by substitution: y = -x + 2 and x + y = 5.

  5. MultiChoice

    Solve by substitution: x = y - 2 and x - y = 3.

  6. MultiChoice

    Solve by substitution: y = 4x - 1 and 4x - y = -5.

  7. MultiChoice

    Solve by substitution: y = 0.5x + 3 and x - 2y = 4.

  8. MultiChoice

    Solve by substitution: y = -2x + 3 and 2x + y = 8.

  9. MultiChoice

    When substituting y = 2x - 1 into 2x - y = 5, we get 1 = 5. What does this mean?

  10. MultiChoice

    Solve by substitution: x = 3y + 2 and x - 3y = -1.

  11. MultiChoice

    Solve by substitution: y = x + 7 and y - x = 2.

  12. MultiChoice

    Solve by substitution: y = 5x - 2 and 5x - y = 10.