Form 14: Real-World Contexts - Perimeter and Dimensions Exercise

Form 14: Real-World Contexts - Perimeter and Dimensions

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Form 14: Real-World Contexts - Perimeter and Dimensions

Solve real-world word problems involving geometric concepts like perimeter and dimensions using two-step inequalities. Set up and solve inequalities to find allowable measurements.

Questions

  1. MultiChoice

    A rectangle has width 5 cm and length x. Perimeter is at most 30 cm. Solve 2x + 10 <= 30.

  2. MultiChoice

    An isosceles triangle has two equal sides of length x and base 8 cm. Perimeter is greater than 24 cm. Solve 2x + 8 > 24.

  3. MultiChoice

    A garden width is x meters, length is 12 meters. Fencing available is at most 40 meters. Solve 2x + 24 <= 40.

  4. MultiChoice

    A square photo with side s has a 2-inch border added to one side. Total perimeter is at least 30 inches. Solve 4s + 2 >= 30.

  5. MultiChoice

    A rectangular rug has length (x + 3) feet and width 4 feet. Perimeter cannot exceed 26 feet. Solve 2x + 14 <= 26.

  6. MultiChoice

    A triangular banner has base 10 inches and two equal sides of length y. Perimeter is at most 36 inches. Solve 2y + 10 <= 36.

  7. MultiChoice

    A pool perimeter must be at least 60 feet. Width is 15 feet and length is L. Solve 2L + 30 >= 60.

  8. MultiChoice

    A fence around a field with width 20 m and length L uses less than 100 m. Solve 2L + 40 < 100.

  9. MultiChoice

    A box base perimeter is 2w + 16. Perimeter must be no more than 40 cm. Solve 2w + 16 <= 40.

  10. MultiChoice

    An equilateral triangle side s is increased by 4 cm. New perimeter is at least 27 cm. Solve 3s + 12 >= 27.

  11. MultiChoice

    A billboard perimeter is 2x + 50 meters and must exceed 90 meters. Solve 2x + 50 > 90.

  12. MultiChoice

    A picture frame perimeter is 2w + 20 and must be less than 50 inches. Solve 2w + 20 < 50.